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M. J. Mardanov 1 and N. I. Mahmudov 2, 3 and Y. A. Sharifov 3, 4
Academic Editor:A. Atangana and Academic Editor:A. Secer
1, Institute of Mathematics and Mechanics, ANAS, B. Vahabzade Street 9, 1141 Baku, Azerbaijan
2, Department of Mathematics, Eastern Mediterranean University, Gazimagusa, North Cyprus, Mersin 10, Turkey
3, Institute of Cybernetics, ANAS, B. Vahabzade Street 9, 1141 Baku, Azerbaijan
4, Baku State University, Z. Khalilov Street 23, 1148 Baku, Azerbaijan
Received 5 December 2013; Accepted 16 February 2014; 23 March 2014
This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
1. Introduction
For the last decades, fractional calculus has received a great attention because fractional derivatives provide an excellent tool for the description of memory and hereditary properties of various processes of science and engineering. Indeed, we can find numerous applications in viscoelasticity [1-3], dynamical processes in self-similar structures [4], biosciences [5], signal processing [6], system control theory [7], electrochemistry [8], and diffusion processes [9].
On the other hand, the study of dynamical systems with impulsive effects has been an object of intensive investigations in physics, biology, engineering, and so forth. The interest in the study of them is that the impulsive differential systems can be used to model processes which are subject to abrupt changes and which cannot be described by the classical differential problems (e.g., see [10-13] and references therein). Cauchy problems, boundary value problems, and nonlocal problems for impulsive fractional differential equations have been attractive to many researchers; one can see [10-22] and references therein.
Feckan et al. [22] investigated the existence and uniqueness of solutions for [figure omitted; refer to PDF] where c D 0 + α denotes the Caputo fractional derivative of order α ∈ ( 0,1 ) and f : J × R [arrow right] R is a given continuous function.
In [21], Guo and Jiang discussed the existence of solutions for the following nonlinear fractional differential equations with boundary value conditions: [figure omitted; refer to PDF] where c D 0 + α is the Caputo fractional derivative of order α ∈ ( 0,1 ) with the lower limit zero, f : J × R [arrow right] R is jointly continuous, t k satisfy 0 = t < t 1 < ... < t p < t p + 1 = T , x ( t k + ) = lim ... [straight epsilon] [arrow right] 0 + x ( t k + [straight epsilon] ) and x ( t k - ) = lim ... [straight epsilon] [arrow right] 0 + x ( t k - [straight epsilon] ) represent the right and left limits of x ( t ) at t = t k , I k ∈ C ( R , R ) , and a , b , c are real constants with a + b ...0; 0 .
Ashyralyev and Sharifov [20] considered nonfractional n -dimensional analogues of the problem (2) with two-point and integral boundary conditions.
Motivated by the papers above, in this paper, we study impulsive fractional differential equations with the two-point and integral boundary conditions in the following form: [figure omitted; refer to PDF] where A , B ∈ R n × n are given matrices and det( A + B ) ...0; 0 . Here f , g : [ 0 , T ] × R n [arrow right] R n and I i : R n [arrow right] R n are given functions.
The rest of the paper is organized as follows. In Section 2, we give some notations, recall some concepts, and introduce a concept of a piecewise continuous solution for our problem. In Section 3, we give two main results: the first result based on the Banach contraction principle and the second result based on the Schaefer fixed point theorem. Some examples are given in Section 4 to demonstrate the application of our main results.
2. Preliminaries
In this section, we introduce notations, definitions, and preliminary facts that will be used in the remainder of this paper. By C ( J , R n ) we denote the Banach space of all continuous functions from J to R n with the norm [figure omitted; refer to PDF] where | · | is the norm in space R n . We also introduce the Banach space [figure omitted; refer to PDF] with the norm [figure omitted; refer to PDF] If A ∈ R n × n , then || A || is the norm of A .
Let us recall the following known definitions and results. For more details see [15, 16].
Definition 1.
If g ∈ C [ a , b ] and α > 0 , then the Riemann-Liouville fractional integral is defined by [figure omitted; refer to PDF] where Γ ( · ) is the Gamma function defined for any complex number z as [figure omitted; refer to PDF]
Definition 2.
The Caputo fractional derivative of order α > 0 of a continuous function g : [ a , b ] [arrow right] R is defined by [figure omitted; refer to PDF] where n = [ α ] + 1 (the notation [ α ] stands for the largest integer not greater than α ).
Remark 3.
Under natural conditions on g ( t ) , the Caputo fractional derivative becomes the conventional integer order derivative of the function g ( t ) as α [arrow right] n .
Remark 4.
Let α , β > 0 and n = [ α ] + 1 ; then the following relations hold: [figure omitted; refer to PDF]
Lemma 5.
For α > 0 , g ( t ) ∈ C [ 0 , T ] ... ... L 1 [ 0 , T ] , the homogeneous fractional differential equation, [figure omitted; refer to PDF] has a solution [figure omitted; refer to PDF] where c i ∈ R , i = 0,1 , ... , n - 1 , and n = [ α ] + 1 .
Lemma 6.
Assume that g ( t ) ∈ C [ 0 , T ] ... ... L 1 [ 0 , T ] , with derivative of order n that belongs to C [ 0 , T ] ... ... L 1 [ 0 , T ] ; then [figure omitted; refer to PDF] where c i ∈ R , i = 0,1 , ... , n - 1 , and n = [ α ] + 1 .
Lemma 7.
Let p , q ...5; 0 , f ∈ L 1 [ 0 , T ] . Then [figure omitted; refer to PDF] is satisfied almost everywhere on [ 0 , T ] . Moreover, if f ∈ C [ 0 , T ] , then (14) is true for all t ∈ [ 0 , T ] .
Lemma 8.
If α > 0 , f ∈ C ( [ 0 , T ] ) , then c D 0 + α I 0 + α f ( t ) = f ( t ) for all t ∈ [ 0 , T ] .
We define a solution problem (3) as follows.
Definition 9.
A function x ∈ P C ( J , R n ) is said to be a solution of problem (3) if c D 0 + α x ( t ) = f ( t , x ( t ) ) , for t ∈ [ 0 , T ] , t ...0; t i , i = 1,2 , ... , p , and for each i = 1,2 , ... , p , x ( t i + ) - x ( t i ) = I i ( x ( t i ) ) , 0 = t 0 < t 1 < t 2 < ... < t p < t p + 1 = T , and the boundary conditions A x ( 0 ) + B x ( T ) = ∫ 0 T ... g ( s , x ( s ) ) d s are satisfied.
We have the following result which is useful in what follows.
Theorem 10.
Let f , g ∈ C ( J , R n ) . Then the function x is a solution of the boundary value problem for impulsive differential equation [figure omitted; refer to PDF] if and only if [figure omitted; refer to PDF] where [figure omitted; refer to PDF]
Proof.
Assume that x is a solution of the boundary value problem (15); then we have [figure omitted; refer to PDF] If t 1 < t ...4; t 2 , then [figure omitted; refer to PDF]
Integrating the expression (19) from t 1 to t , one can obtain [figure omitted; refer to PDF] It follows that [figure omitted; refer to PDF]
Thus if t ∈ ( t k , t k + 1 ] , we get [figure omitted; refer to PDF] where x ( 0 ) is still an arbitrary constant vector. For determining x ( 0 ) we use the boundary value condition A x ( 0 ) + B x ( T ) = ∫ 0 T ... g ( s ) d s : [figure omitted; refer to PDF] Hence, we obtain [figure omitted; refer to PDF] and consequently for all t ∈ ( t k , t k + 1 ] [figure omitted; refer to PDF]
Conversely, assume that x satisfies (16). If t ∈ [ 0 , t 1 ] , then, using the fact that c D 0 + α is the left inverse of I 0 + α , we get D 0 + α c x ( t ) = f ( t ) , t 0 < t ...4; t 1 . If t ∈ ( t k , t k + 1 ] , k = 1,2 , ... , p , then, using the fact that the Caputo derivative of a constant is equal to zero, we obtain D 0 + α c x ( t ) = f ( t ) , t k < t ...4; t k + 1 , and x ( t k + ) - x ( t k ) = I k ( x ( t k ) ) . The lemma is proved.
Theorem 11 (see [18]).
Let X be a Banach space and W ⊂ P C ( J , X ) . If the following conditions are satisfied,
(1) W is uniformly bounded subset of P C ( J , X ) ,
(2) W is equicontinuous in ( t k , t k + 1 ) , k = 0,1 , 2 , ... , p , where t 0 = 0 , t p + 1 = T ,
(3) W ( t ) = { u ( t ) : u ∈ W , t ∈ J [variant prime] } , W ( t k + ) = { u ( t k + ) : u ∈ W } , and W ( t k - ) = { u ( t k - ) : u ∈ W } are relatively compact subsets of X ,
then W is a relatively compact subset of P C ( J , X ) .
3. Main Results
Our first result is based on Banach fixed point theorem. Before stating and proving the main results, we introduce the following hypotheses.
(H1) f , g : J × R n [arrow right] R n are continuous functions.
(H2) There are constants L f > 0 and L g > 0 such that [figure omitted; refer to PDF]
: for each t ∈ [ 0 , T ] and all x , y ∈ R n .
(H3) There exist constants l i > 0 , i = 1,2 , ... , p such that [figure omitted; refer to PDF]
: for all x , y ∈ R n .
For brevity, let [figure omitted; refer to PDF]
Theorem 12.
Assume that (H1)-(H3) hold. If [figure omitted; refer to PDF] then the boundary value problem (3) has a unique solution on J .
Proof.
The proof is based on the classical Banach fixed theorem for contractions. Let us set [figure omitted; refer to PDF] It is clear that [figure omitted; refer to PDF] Consider [figure omitted; refer to PDF] where [figure omitted; refer to PDF]
Let Q be the following operator: [figure omitted; refer to PDF] We show that Q maps B r into B r . It is clear that Q is well defined on P C ( J , R n ) . Moreover for x ∈ B r and t ∈ ( t k , t k + 1 ] , k = 0 , ... , p , we have [figure omitted; refer to PDF] Consequently Q maps P C ( J , R n ) into itself.
Next we will show that Q is a contraction. Let x , y ∈ P C ( J , R n ) . Then, for each t ∈ ( t k , t k + 1 ] , k = 0 , ... , p , we have [figure omitted; refer to PDF] Thus, Q is a contraction mapping on P C ( J , R n ) due to condition (29) and the operator Q has a unique fixed point on P C ( J , R n ) which is a unique solution to (3).
The second result is based on the Schaefer fixed point theorem. We introduce the following assumptions.
(H4) There exist constants N f > 0 , N g > 0 such that | f ( t , x ) | ...4; N f , | g ( t , x ) | ...4; N g for each t ∈ J and all x ∈ R n .
(H5) I k ∈ C ( R n , R n ) .
Theorem 13.
Assume that (H1), (H4), and (H5) hold. Then the boundary value problem (3) has at least one solution on J .
Proof.
We will use Schaefer's fixed point theorem to prove that Q defined by (34) has a fixed point. The proof will be given in several steps.
Step 1 . Operator Q is continuous.
Let { x n } be a sequence such that x n [arrow right] x in P C ( J , R n ) . Then, for each k = 0,1 , 2 , ... , p and for all t ∈ ( t k , t k + 1 ] , we have [figure omitted; refer to PDF] Since f , g , and I k , k = 0,1 , 2 , ... , p , are continuous functions, we have [figure omitted; refer to PDF] as n [arrow right] ∞ .
Step 2 . Q maps bounded sets in bounded sets in P C ( J , R n ) .
Indeed, it is enough to show that, for any η > 0 , there exists a positive constant l such that, for each x ∈ B η = { x ∈ P C ( J , R n ) : || x || P C ...4; η } , we have || Q ( x ) || P C ...4; l . By (H4), (H5) we have, for each k = 1,2 , ... , p and for all t ∈ ( t k , t k + 1 ] , [figure omitted; refer to PDF] Thus [figure omitted; refer to PDF]
Step 3 . Q maps bounded sets into equicontinuous sets of P C ( J , R n ) .
Let τ 1 , τ 2 ∈ ( t k , t k + 1 ] , τ 1 < τ 2 , B η be a bounded set of P C ( J , R n ) as in Step 2, and let x ∈ B η . Then [figure omitted; refer to PDF] As τ 1 [arrow right] τ 2 , the right-hand side of the above inequality tends to zero.
As a consequence of Steps 1 to 3 together with the Arzela-Ascoli theorem (Theorem 11 with X = R n ), we can conclude that the operator Q : P C ( J , R n ) [arrow right] P C ( J , R n ) is completely continuous.
Step 4 . One has a priori bounds.
Now it remains to show that the set [figure omitted; refer to PDF] is bounded.
Let then x = λ Q ( x ) for some 0 < λ < 1 . Thus, for each t ∈ ( t k , t k + 1 ] , we have [figure omitted; refer to PDF] Thus [figure omitted; refer to PDF] This shows that the set Δ is bounded. As a consequence of Schaefer's fixed point theorem, we deduce that Q has a fixed point which is a solution of the problem (3).
4. Examples
In this section, we give some examples to illustrate our main results.
Example 1.
Consider [figure omitted; refer to PDF] Consider boundary value problem (3) with f 1 ( t , x 1 , x 2 ) = cos ... ( ( 1 / 10 ) x 2 ( t ) ) , f 2 ( t , x 1 , x 2 ) = ( e - t / ( 9 + e t ) ) · ( | x 1 | / ( 1 + | x 1 | ) ) , and T = 1 , p = 1 , I 1 ( x 1 , x 2 ) = [ ( 1 / 10 ) x 2 ( 1 / 10 ) x 1 + 5 ] .
Evidently, [figure omitted; refer to PDF] and conditions (H1)-(H3) hold. We will show that condition (29) is satisfied for, say, α = 0,2 . Indeed, [figure omitted; refer to PDF] where we used [figure omitted; refer to PDF]
Then, by Theorem 12, boundary value problem (45) has unique solution on [ 0,2 ] .
Example 2.
Consider [figure omitted; refer to PDF]
Here 0 < α ...4; 1 , f 1 ( t , x 1 , x 2 ) = e - t / ( 1 + x 2 2 ( t ) ) , f 2 ( t , x 1 , x 2 ) = sin x 1 ( t ) , A = ( 1 0 0 1 ) , B = ( 0 0 0.5 0 ) , and T = 1 , p = 1 , I 1 ( x 1 , x 2 ) = [ 1 / ( 1 + x 2 2 ) 1 / ( 1 + cos ... 2 x 1 ) ] . Clearly, all the conditions of Theorem 13 are satisfied ( N f = 1 , N g = 0 ) , and consequently boundary value problem (49) has at least one solution.
Conflict of Interests
The authors declare that there is no conflict of interests regarding the publication of this paper.
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Abstract
We study a boundary value problem for the system of nonlinear impulsive fractional differential equations of order α 0 < α ...4; 1 involving the two-point and integral boundary conditions. Some new results on existence and uniqueness of a solution are established by using fixed point theorems. Some illustrative examples are also presented. We extend previous results even in the integer case α = 1 .
You have requested "on-the-fly" machine translation of selected content from our databases. This functionality is provided solely for your convenience and is in no way intended to replace human translation. Show full disclaimer
Neither ProQuest nor its licensors make any representations or warranties with respect to the translations. The translations are automatically generated "AS IS" and "AS AVAILABLE" and are not retained in our systems. PROQUEST AND ITS LICENSORS SPECIFICALLY DISCLAIM ANY AND ALL EXPRESS OR IMPLIED WARRANTIES, INCLUDING WITHOUT LIMITATION, ANY WARRANTIES FOR AVAILABILITY, ACCURACY, TIMELINESS, COMPLETENESS, NON-INFRINGMENT, MERCHANTABILITY OR FITNESS FOR A PARTICULAR PURPOSE. Your use of the translations is subject to all use restrictions contained in your Electronic Products License Agreement and by using the translation functionality you agree to forgo any and all claims against ProQuest or its licensors for your use of the translation functionality and any output derived there from. Hide full disclaimer