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Academic Editor:Wanbiao Ma
College of Mathematics and System Sciences, Xinjiang University, Urumqi, Xinjiang 830046, China
Received 24 June 2014; Accepted 15 September 2014; 20 October 2014
This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
1. Introduction
As we all know, the use of heroin and other drugs in Europe and more specifically in Ireland and the resulting prevalence are well documented [1-3]. It shows that the use of heroin is very popular and causes many preventable deaths. Heroin is so soluble in the fat cells that it crosses the blood-brain barrier within 15-20 seconds, rapidly achieving a high level syndrome in the brain and central nervous system which causes both the "rush" experience by users and the toxicity. Heroin-related deaths are associated with the use of alcohol or other drugs [4]. Treatment of heroin users is a huge burden on the health system of any country.
We often study infectious diseases with mathematical and statistical techniques; see, for example, [5-11]; however, little has been done to apply this method to the heroin epidemics. In 1979, Mackintosh and Stewart [9] considered an exponential model which is simplified from infectious disease model of Kermack and McKendrick to illustrate how the heroin-using spreads in epidemic fashion. They arranged a numerical simulation to show how the dynamics of spread are influenced by parameters in the model. White and Comiskey [5] attempted to extend dynamic disease modeling to the drug-using career and formulated an ordinary differential equation. They divided the whole population into three classes, namely, susceptible, heroin users, and heroin users undergoing treatment. Their model allows a steady state (constant) solution which represents an equilibrium between the number of susceptible, heroin users, and heroin users in treatment. Furthermore, this ODE model was revisited by Mulone and Straughan [12]; the authors proved that this equilibrium solution is stable both linearly and nonlinearly under the realistic condition in which relapse rate of those in treatment returning to untreated drug use is greater than the prevalence rate of susceptible becoming drug users. Recently, the study of the global properties and permanence of continuous heroin epidemic models attracted the researchers and have some very good results; see [13-16]. Specially, Samanta [15] considered a model with time-dependent coefficients and with different removal rates for three different classes, introduced some new threshold values R* and R* , and obtained the permanence of heroin-using career.
Motivated by Samanta [15] and Zhang and Teng [8], we alter a nonautonomous heroin epidemic model with time delay to an autonomous heroin epidemic model. For convenience, we replace U1 and U2 by U and V , respectively. Thus, we obtain the following continuous heroin epidemic model with a distributed time delay: [figure omitted; refer to PDF] where S(t) , U(t) , and V(t) represent the number of susceptible, heroin users not in treatment, and heroin users in treatment, respectively. We assume that the time taken to become heroin user is s . The function η(s):[0,h][arrow right][0,∞) is nondecreasing and has bounded variation such that ∫0h ...η(s)ds=η(h)-η(0)=1 .
For understanding more realistic phenomenon of heroin, a little complicated epidemic model is helpful. By applying Micken's nonstandard discretization method [17] to continuous heroin epidemics model with time delay (1), we derive the following discretized heroin epidemic model with a distributed time delay: [figure omitted; refer to PDF] where Sn is the susceptible class, Un is the class of heroin users not in treatment, and Vn is the class of heroin users in treatment at n th step. Since the sufficient condition can be obtained, independently of the choice of a time step-size, we let the time step-size be one for the sake of simplicity. The nonnegative constants μ1 , μ2 , and μ3 denote the death rate of the susceptible, heroin users not in treatment, and heroin users in treatment class, respectively. Throughout the paper, it is biologically natural to assume that μ1 ...4;min...{μ2 ,μ3 } . The constant λ>0 denotes the recruitment rate of susceptible population from the general population. Constant P>0 is the proportion of heroin users who enter the treatment class. The individuals in treatment who stop using heroin are susceptible at a constant rate ξ2 ...5;0 . Constant β3 represents the transmission rate from heroin users in treatment to untreated heroin users. β1 (Un ) is the probability per unit time and the transmission is used with the form β1 (Un )Sn+1∑k=0h ...Un-kηk , which includes various delays. By a natural biological meaning, we assume that β1 (U) is a positive function and that there exists a constant Uβ >0 such that β1 (U) is nondecreasing on the interval [0,Uβ ] . The integer h...5;0 is the time delay. The sequence ηk :-∞<ηk <+∞ (k=0,1,...,h) is nondecreasing and has bounded.
The initial conditions of the system (2) are given by [figure omitted; refer to PDF] where ψn(i) ...5;0 (n=-h,-h+1,...,0, i=1,2,3) . Again, by biological meaning, we further assume that ψ0(i) >0 for all i=1,2,3 .
The paper is organized as follows. In Section 2, we prove the positivity and boundedness of the solution of system (2). In Section 3, we deal with the global asymptotic stability of the heroin-using free equilibrium. In Section 4, we consider the permanence of the discrete epidemic model applying Wang's technique. In the discretized epidemic model, sufficient condition for global asymptotic stability and permanence are the same as for the original continuous epidemic model. We give some numerical examples and conclusion in Sections 5 and 6.
2. Basic Properties
For system (2), the heroin-using free equilibrium is given by [figure omitted; refer to PDF] Define a positive constant A...1;∑k=0h ...ηk . The stability of E0 is studied by using the next generation method in [7]. The associated matrix F (of the new heroin-using terms) and the M-matrix V (of the remaining transfer terms) are given as follows, respectively: [figure omitted; refer to PDF] Clearly, F is nonnegative, V is a nonsingular M-matrix, and V-F has Z sign pattern. The associated basic reproduction number, denoted by R0 , is then given by R0 =ρ(FV-1 ) , where ρ is the spectral radius of FV-1 . It follows that [figure omitted; refer to PDF]
Now, we will consider the positivity and boundedness of solution to system (2). For most continuous epidemic models, positivity of the solution is clear, but, for system (2), the positivity of the sequences Sn ,Un , and Vn holds in some condition.
Lemma 1.
Let (Sn ,Un ,Vn ) be any solution of system (2) with initial condition (3); then (Sn ,Un ,Vn ) is positive for any n∈N and V0 <P(1+μ3 +ξ2 )/β3 .
Proof.
Let (Sn ,Un ,Vn ) be any solution of system (2) with initial condition (3). It is evident that system (2) is equivalent to the following iteration system: [figure omitted; refer to PDF] In the following, we will use the induction to prove the positivity of solution. When n=0 , we have [figure omitted; refer to PDF] From (8)-(10), we see that, as long as U1 is obtained, V1 and S1 will be obtained too.
If U1 >0 , from (9), we directly obtain V1 >0 and, from (10), we further obtain that S1 >0 . Furthermore, we also have N1 =S1 +U1 +V1 >0 .
Let x=U1 ; then, from (8)-(10), we see that x satisfies the following equation: [figure omitted; refer to PDF] where [figure omitted; refer to PDF] Substituting V1 in W2 (x) gets [figure omitted; refer to PDF] Since V0 <P(1+μ3 +ξ2 )/β3 , we have [figure omitted; refer to PDF] and because of W1 (0)=λ+S0 +ξ2V0 /(1+μ3 +ξ2 )>0 , thus [figure omitted; refer to PDF] Substituting W1 and W2 in ψ(x) yields [figure omitted; refer to PDF] Here, constants a , b , c , m , and n are as follows: [figure omitted; refer to PDF] We take the limit on both sides of the above equation: [figure omitted; refer to PDF] this means that ψ(x)=0 has at least one positive solution x-∈(0,+∞) . So, we have U1 =x->0 . Therefore, the positivity of S1 >0 , U1 >0 , and V1 >0 is finally obtained. When n=2 , we have [figure omitted; refer to PDF] a similar argument as in the above for U1 , V1 , and S1 ; we also can obtain that U2 >0 , V2 >0 , and S2 >0 . Lastly, by using the induction, we can finally obtain that Sn >0 , Un >0 , and Vn >0 , for all n>0 .
Now, we define the total population as Nn =Sn +Un +Vn . Then, from system (2), we know that [figure omitted; refer to PDF] Notice the assumption that μ1 ...4;min...(μ2 ,μ3 ) ; we obtain [figure omitted; refer to PDF] If λ/μ1 ...5;N0 , it is easy to see that Nn ...4;λ/μ1 =S0 , for all large n . If λ/μ1 <N0 , from right hand side of system (2), we obtain [figure omitted; refer to PDF] Hence, we have N1 <N0 and there exists i∈N such that Ni ...4;λ/μ1 =S0 . Then, we may use this Ni as a starting value instead of N0 . This argument leads to the following result.
Lemma 2.
For any solution (Sn ,Un ,Vn ) of system (2), the total population Nn =Sn +Un +Vn satisfies [figure omitted; refer to PDF] thus (Sn ,Un ,Vn ) is ultimately bounded.
Let Ω={(Sn ,Un ,Vn ):Sn ,Un ,Vn ...5;0, Sn +Un +Vn ...4;λ/μ1 } ; then Ω is the positive invariant set to the solution of system (2).
In the following, we will examine the existence of endemic equilibrium for a special case of system (2).
Lemma 3.
Assume that β1 (U)=β1 >0 is a constant. If R0 >1 , system (2) admits a heroin-using equilibrium E* =(S* ,U* ,V* ) when V<P/β3 , where E* satisfies following equality: [figure omitted; refer to PDF]
Proof.
Consider the following equation: [figure omitted; refer to PDF] From the first equation and the second equation of the system (25), we have [figure omitted; refer to PDF] From the second equation and the third equation of the system (25), we obtain [figure omitted; refer to PDF] thus, [figure omitted; refer to PDF] Since U...0;0 , from the second equation of the system, we have [figure omitted; refer to PDF] Substituting S in (28), we obtain [figure omitted; refer to PDF] Substituting U and S in (26) yields a quadratic equation of V as follows: [figure omitted; refer to PDF] where the coefficients are given by [figure omitted; refer to PDF] Since R0 =λAβ1 /μ1 (μ2 +P+ξ1 )>1 , then it is easy to see that c<0 and b>0 . According to Descartes' rule of signs, if a...5;0 , then F(V)=0 has a positive solution; if a<0 , then F(V)=0 has two positive solutions. From the expression of S and U , we note that V<P/β3 . Since [figure omitted; refer to PDF] This means that F(V)=0 has a unique positive solution V* ∈(0,P/β3 ) . Therefore, there exists a unique positive solution (S* ,U* ,V* ) of system (2).
For the local stability of the equilibria, we refer to Theorem 2 in [7] and have the following results.
Theorem 4.
Assume that β1 (U)=β1 , β1 is a positive constant. The heroin-using free equilibrium E0 =(S0 ,0,0) of system (2) is locally asymptotically stable if R0 <1 and unstable if R0 >1 .
3. Global Asymptotic Stability of the Heroin-Using Free Equilibrium
In this section, we still assume that β1 (U)=β1 >0 , and obtain a sufficient condition for global asymptotic stability of the heroin-using free equilibrium E0 of system (2).
Using a Lyapunov function similar to that in [11], we can easily prove the global asymptotic stability of the heroin-using free equilibrium E0 .
Theorem 5.
If R0 <1 , the drug-using free equilibrium E0 of system (2) is globally asymptotically stable.
Proof.
Let us take the following Lyapunov function: [figure omitted; refer to PDF] where ci >0 (i=1,2,3) are the constants to be defined later and S0 =λ/μ1 . Using system (2), the difference of Hn satisfies [figure omitted; refer to PDF] From Sn ...4;Nn ...4;S0 , for all n...5;0 , we have [figure omitted; refer to PDF] Let us choose ci >0 (i=1,2,3) such that these constants satisfy the following inequalities: [figure omitted; refer to PDF] From (37), we have c3β1Sn+12 +(c3β1S0 -β1 )Sn+1 +c2 >0 ; since Sn+1 >0 , then the following inequality is true: [figure omitted; refer to PDF] that is, [figure omitted; refer to PDF] Since R0 <1 , which implies that β1 AS0 <μ2 +P+ξ1 , we can choose c2 =β1S0 +... ; here, ... (0<...<(μ2 +ξ1 -Aβ1S0 )/A) is a sufficiently small positive number such that β1 AS0 +A...<μ2 +(1-c1 )P+ξ1 . Since β1S0 -2c2 <0 and (β1S0 -2c2)2 >(β1S0)2 , we can choose c3 >0 to satisfy (41). We may further choose c1 >1 to satisfy (38). Therefore, ΔH is negative definite and is equal to zero if and only if Sn+1 =S0 , Un+1 =0 , and Vn+1 =0 . The proof is complete.
4. Permanence of System (2)
The system (2) is said to be permanent if there are positive constants m and M such that [figure omitted; refer to PDF] hold for any sequence Sn of the system (2), and the same inequalities hold for Un and Vn . For each class Sn ,Un , and Vn , m and M are independent of initial conditions.
Following the method used by Wang in [6], we will prove the permanence of system (2) for the general case; that is, assume that β1 (U) is related to U .
Theorem 6.
If R0 >1 , then system (2) is permanent for any initial condition (3).
Proof.
Firstly, from system (2) and Lemmas 1 and 2, for any ...0 >0 , there exists sufficiently large n0 >0 such that Un ...4;λ/μ1 +...0 as n...5;n0 +h . Then, we have [figure omitted; refer to PDF] Let β1M (...0 )=max...U∈[0,λ/μ1 +...0 ]β1 (U) . Thus, we have [figure omitted; refer to PDF] Notice that ...0 can be arbitrarily small. Then, we have [figure omitted; refer to PDF] Next, let us consider the positive sequences Sn and Un of (2). According to these sequences, we define [figure omitted; refer to PDF] Then, for n...5;0 , we obtain [figure omitted; refer to PDF] Since R0 =β1 (0)Aλ/μ1 (μ2 +P+ξ1 )>1 , there exist 0<α<Uβ and ρ>0 such that [figure omitted; refer to PDF] note that [figure omitted; refer to PDF]
We claim that it is impossible that Un ...4;α holds for all n...5;n1 ...5;[ρh] . The function [x] gives the smallest integer not less than x . Suppose the contrary, for n...5;n1 +h . Consider [figure omitted; refer to PDF] From Lemma 1, Sn satisfies [figure omitted; refer to PDF] and we have that, for n...5;n1 +h+[ρh] , we have [figure omitted; refer to PDF] Hence, for n...5;n1 +h+[ρh] , we have [figure omitted; refer to PDF] Let ...=min...θ {Un1 +[ρh]+h+θ ;θ=-h,-h+1,...,0} . Now, we will show that Un ...5;... for all n...5;n1 +[ρh]+h . In fact, there is an integer n->0 such that [figure omitted; refer to PDF] However, for n=n1 +[ρh]+h+n- , we have [figure omitted; refer to PDF] Which is a contradiction. Thus, Un ...5;... for n...5;n1 +[ρh]+h . Therefore, for n...5;n1 +[ρh]+h , [figure omitted; refer to PDF] which implies that Hn [arrow right]+∞ as n[arrow right]+∞ . But, from Lemma 2 and (46), there exists a sufficiently large integer n1[variant prime] >0 such that, for n>n1[variant prime] , [figure omitted; refer to PDF] which is a contradiction. Hence, the claim is proved.
In the rest, we only need to consider the following two cases:
(i) Un ...5;α for all large n .
(ii) Un oscillates about α for all large n .
We show that Un ...5;mu for all large n , where 0<mu ...4;α , is a constant which will be given later. Clearly, we only need to consider case (ii). Let positive integers n1 and n2 be sufficiently large that Un1 ...5;α , Un2 ...5;α , and Un <α , for n1 <n<n2 .
If n2 -n1 <h+[ρh] , since [figure omitted; refer to PDF] we have [figure omitted; refer to PDF] Hence, Un >mu for n∈[n1 ,n2 ] .
If n2 -n1 >h+[ρh] , we can easily obtain that Un >mu for n∈[n1 ,n1 +h+[ρh]] . Assume that there exists an integer n^>0 such that [figure omitted; refer to PDF] However, for n=n1 +h+[ρh]+n^ , [figure omitted; refer to PDF] This is a contradiction to the proposition that Un+1 <mu . Therefore, Un ...5;mu for n∈[n1 ,n2 ] . Since these positive integers n1 and n2 are chosen in an arbitrary way, we conclude that Un ...5;mu for all large n in case (ii). Hence, liminf...n[arrow right]∞Un ...5;mu .
Note that, from that third equation of system (2), we have [figure omitted; refer to PDF] From Lemma 2 and the discussion above, we have [figure omitted; refer to PDF] The proof is completed.
5. Numerical Example
In order to confirm the validity of our results, we consider the following heroin epidemic model with a discrete time delay: [figure omitted; refer to PDF] Now, we present a numerical example. For the sake of simplicity, we choose the parameters as β1 =0.9 , β3 =0.8 , λ=2 , μ1 =0.1 , μ2 =0.2 , μ3 =0.1 , P=0.4 , ξ1 =0.1 , and ξ2 =0.2 ; we get R0 =25.7143<1 . Figure 1 shows that the disease free equilibrium E0 of the system (64) is globally asymptotically stable when R0 <1 . Figure 2 shows that the system (64) is permanent when R0 >1 .
Figure 1: [figure omitted; refer to PDF]
Figure 2: [figure omitted; refer to PDF]
6. Conclusions
In this paper, we have modified the Samanta heroin epidemic model into an autonomous heroin epidemic model with distributed time delay. Further, we established a discretized heroin epidemic model with time delay, sufficient conditions have been obtained to ensure the global asymptotic stability of heroin-using free equilibrium when R0 ...4;1 and β1 (U) is replaced by a positive constant. We also carried out some discussion about the heroin-using equilibrium, but our results are only restricted to the existence of this equilibrium for β1 (U)=β1 >0 , a special case of system (2). The stability of heroin-using equilibrium is yet to be studied. As a main result of this paper, we obtained the permanence of the system (2). From the expression of R0 =β1 (0)λA/μ1 (μ2 +P+ξ1 ) , we see that a decrease in β1 (transmission coefficient from susceptible population) will cause a decrease of the same proportion in R0 . If the rate of migration or recruitment is restricted into susceptible community, the spread of the disease can also be kept under control by reducing λ and thereby decreasing R0 . The spread of the heroin users can also be controlled by educators, epidemiologists, and treatment providers to increase the values of ξ (removal rate of heroin users not in treatment who stop using heroin but are susceptible) and P (proportion of heroin users who enter treatment) and thereby to decrease R0 . This analysis tells us that prevention is better than cure; efforts to increase prevention are more effective in controlling the spread of habitual drug use than efforts to increase the numbers of individuals accessing treatment.
Acknowledgment
This work was supported by the National Natural Science Foundation of China (Grants nos. 11261056, 11261058, and 11271312).
Conflict of Interests
The authors declare that there is no conflict of interests regarding the publication of this paper.
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Copyright © 2014 Xamxinur Abdurahman et al. Xamxinur Abdurahman et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
Abstract
We derive a discretized heroin epidemic model with delay by applying a nonstandard finite difference scheme. We obtain positivity of the solution and existence of the unique endemic equilibrium. We show that heroin-using free equilibrium is globally asymptotically stable when the basic reproduction number [subscript]R0[/subscript] <1 , and the heroin-using is permanent when the basic reproduction number [subscript]R0[/subscript] >1 .
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Neither ProQuest nor its licensors make any representations or warranties with respect to the translations. The translations are automatically generated "AS IS" and "AS AVAILABLE" and are not retained in our systems. PROQUEST AND ITS LICENSORS SPECIFICALLY DISCLAIM ANY AND ALL EXPRESS OR IMPLIED WARRANTIES, INCLUDING WITHOUT LIMITATION, ANY WARRANTIES FOR AVAILABILITY, ACCURACY, TIMELINESS, COMPLETENESS, NON-INFRINGMENT, MERCHANTABILITY OR FITNESS FOR A PARTICULAR PURPOSE. Your use of the translations is subject to all use restrictions contained in your Electronic Products License Agreement and by using the translation functionality you agree to forgo any and all claims against ProQuest or its licensors for your use of the translation functionality and any output derived there from. Hide full disclaimer