1. Introduction
It is a well-known fact that the set ℚ ℚ of rational numbers is not complete—hence, such important constants as 2 2 or π π do not exist in ℚ ℚ . Because the way in which the set ℝ ℝ is constructed of real numbers from ℚ ℚ is quite complicated, it is usually defined axiomatically. The completeness of ℝ ℝ can be formulated in different ways, e.g., as a complete metric space, or as a complete lattice. In [1], a review of some completeness axioms for ℝ ℝ is presented. In this paper, the set ℝ ℝ will be characterized by a property which is very important in the probability theory, which may prove useful from the point of view of applications, as well as didactics. In the paper we shall characterize the set ℝ ℝ from the perspective of the probability theory, namely in the Kolmogorov formulations—an event is a set on certain σ σ -algebra S of subsets of a space Ω Ω , and the probability is a σ σ -additive mapping P:S⟶[0, 1] . In terms of measurement, the mapping is a real function ξ: Ω⟶ℝ , and it is an interesting point, especially in terms of didactics, that the complete information about ξ is obtained from the distribution function F of ξ , which is a real function, F: ℝ⟶[0, 1], with some particular properties.
The paper is organized as follows: In Section 2 we will formulate two different axioms—the supremum axiom (S) and the distribution function axiom (D); and in Section 3 we will prove that the axioms are equivalent.
2. Materials and Methods
In this section we formulate the important properties of the distribution function. In the literature there are two well-established but different definitions of the distribution function F: ℝ⟶[0, 1] of a random variable ξ: Ω⟶ℝ . The first is given by the formula F(x)=P({ω∈Ω: ξ(ω)<x }) , and the second by the formula F(x)=P({ω∈Ω: ξ(ω)≤x}) . In this paper we shall use the second approach, which is more convenient for working with the supremum axiom. Evidently, the first one could be used in the infimum way. The distribution function F: ℝ⟶[0, 1] can be characterized without any reference to the general probability space [2,3] and by applying only a few properties of F, as shown in the following definition.
Definition 1.
A function F: ℝ⟶[0, 1]is called a distribution if it satisfies the following properties:
1. F is non-decreasing
2. F is right continuous in any point x0∈ℝ,
3. limx⇀−∞F(x)=0,
4. limx⇀∞F(x)=1.
In the probability theory, the following theorem presents a translation method between the elementary approach and the abstract theory. To any distribution function F: ℝ⟶[0, 1] there exists a probability measure λ: B⟶[0, 1] defined on the family B of Borel subsets of ℝ, such that:
λ((α, β])=F(β)−F(α)
for any α, β∈ℝ, α<β.
In our elementary approach, instead of B we will work only with the family R for all unions of intervals I⊂ℝ (bounded as well as unbounded). According to the measure extension theorem, any additive and continuous mapping λ: R⟶[0, 1] can be extended from R to B , since R is an algebra and B is the σ -algebra generated by R.
Axiom (S). Any increasing bounded sequence of real numbers has the supremum—the least upper bound of the sequence.
In our distribution axiom, instead of σ-additivity, we shall use the notion of additivity and the notion of continuity.
A mapping λ: R⋃[0, 1] is additive, if for sets A,B∈R such that A⋂B=∅, it holds:
λ(A⟶B)=λ(A)+λ(B).
A mapping λ: R⟶[0, 1] is continuous if, for any An∈R , such that An⊂An+1 (n=1, 2, …) and ⋃n=1∞An∈R, it holds:
λ(⋃n=1 ∞An)=limn→∞λ(An).
Axiom (D). To any distribution function F: ℝ⟶[0, 1] there exists an additive and continuous mapping λ: R⟶[0, 1], such that:
λ((α, β])=F(β)−F(α)
for any (α, β]⊂ℝ.
3. Results
There are many known proofs of the axiom (D), e.g., referring to the completeness of R by (S). Now we shall prove the opposite implication.
Theorem 1.
Axiom (D) implies Axiom (S).
Proof of Theorem 1.
Let {an}n be a sequence, such that 0<a1<a2< ⋯ <an<an+1≤1 . Our goal is to construct a distribution function y=F(x) and an increasing sequence bn , such that F(bn)=an for every n. Consider the points B0, B1, C1 in the coordinate system, where B0=(0, 0), B1=(b1, 0) , and C1=(b1,12) (see Figure 1).
Denote the area of the triangle, defined by these points by a1 . Clearly, b1=4a1. Let x be a point in the interval [0, b1). Then, F(x) is the area of the triangle, defined by points B0, X1=(x, 0) and X2=(x,x8a1) (see Figure 2).
F(x)=x,x8a12= x216a1,
F(b1)=F(4a1)=a1.
.
The constructed point is F(b1)=a1. Consider the points B1, C1, B2, C2 where B2=(b2, 0), C2= =(b2,34) ; the area of the trapezoid defined by these points is a2−a1 (see Figure 3).
(12+34)12(b2−b1)= a2−a1.
Hence,
b2=b1+ 85(a2−a1).
.
Let x∈[b1,b2]. Let F(x) be the area of the trapezoid defined by B0, C1, X1=(x, 0) , X2=(x, 12+x −b14(b2−b1)) (see Figure 4).
F(x)=a1+(12+x−b14(b2−b1)+12 )12(x −b1)
F(b2)=a1+(a2−a1)=a2.
By induction, assume F(bn)=an. Consider the points Cn=(bn, 1−12n), Cn+1=(bn+1, 1−12n+1), Bn=(bn, 0) and Bn+1=(bn+1, 0). These four points define the area an+1−an of the trapezoid (see Figure 5).
(1−12n +1−12n+1)12(bn+1−bn)=an+1−an
bn+1=2n+22n+2−3(an+1−an)+bn.
Let x∈[bn,bn+1], F(x) be the area of the trapezoid, defined by Bn, Cn, X1=(x, 0), X2=(x, x −bn(bn+1−bn)2n+1) (see Figure 6).
F(x) =an+(1−12n+(x −bn)(bn+1−bn)2n+1)(x −bn)
F(bn+1 )=an+an+1−an=an+1.
.
Define function F by using the following properties:
1. For all x≤0 , put F(x)=0.
2. If there exists a natural number n and x∈[bn,bn+1], then
F(x)=an+(1−12n+(x −bn)(bn+1−bn)2n+1)(x −bn),
* if x≥bn for all natural numbers n, then F(x)=1.
It can easily be proved that F is a distribution function. Assume that there exists a probability measure λ: R⟶[0, 1] , such that λ(α, β])=F(β)−F(α) , and in particular, λ((bn−1,bn])=an−an−1.Compute:
λ((−∞,bn])=λ((−∞, 0))+λ((0,b1])+λ((b1,b2])+⋯ + λ((bn−1,bn])=0+(a1−0)+(a2−a1)+⋯ +(an)=an.
Consider:
A=⋃n=1 ∞(−∞, bn).
Then,
λ(A)=limn→∞λ((−∞, bn])=limn→∞an=supn∈N an.
Thus, we have found that any increasing sequence {an}n from the interval [0, 1]has the supremum.
Now, let {an}n be an arbitrary bounded increasing sequence from (0, k]. For any natural n, take cn=ank. Then cn∈(0, 1] , and there exists the supremum of {cn}n. Hence, there exists the supremum of {an}n, and:
sup n∈Nan=k supn∈N cn.
Finally, consider (an)n as an arbitrary increasing bounded sequence. Take dn=an−a1. This means that dn is non-decreasing, non-negative, and bounded. Therefore, there also exists the supremum of dn. Hence, there exists the supremum of anand
supan=a1+supdn.
□ 4. Conclusions
This paper focused on the axiom (D), one of the fundamental axioms in the probability theory. We showed that the axiom (D) is equivalent to the supremum axiom (S) of real numbers. The axiom (D) is crucial for many other important theorems in probability and statistics, such as the laws of large numbers, the central limit theorem, or statistical estimations.
Author Contributions
All the authors contributed the same work.
Funding
This research received no external funding.
Acknowledgments
We would like to acknowledge Renáta Vágová, currently a Ph.D. student at the Department of Mathematics, FNS, Constantine the Philosopher University in Nitra, for drawing the figures.
Conflicts of Interest
The authors declare no conflict of interest.
1. Teissman, H. Toward a More Complete List of Completeness Axiom. Am. Math. Mon. 2013, 120, 99–114.
2. Riečan, B.; Neubrunn, T. Integral, Measure and Ordening; Springer Science & Business Media: Berlin/Heidelberg, Germany, 2013.
3. Billingsley, P. Probability and Measure; John Wiley & Sons: Hoboken, NJ, USA, 2008.
1Department of Mathematics, Faculty of Natural Sciences, Matej Bel University, Tajovského 40, 974 01 Banská Bystrica, Slovakia
2Institute of Mathematics and Computer Science, Mathematical Institute Slovak Academy of Sciences, Štefánikova 49, 814 73 Bratislava, Slovakia
3Department of Mathematics, Faculty of Natural Sciences, Constantine the Philosopher University in Nitra, Tr. A. Hlinku 1, 949 74 Nitra, Slovakia
*Author to whom correspondence should be addressed.
You have requested "on-the-fly" machine translation of selected content from our databases. This functionality is provided solely for your convenience and is in no way intended to replace human translation. Show full disclaimer
Neither ProQuest nor its licensors make any representations or warranties with respect to the translations. The translations are automatically generated "AS IS" and "AS AVAILABLE" and are not retained in our systems. PROQUEST AND ITS LICENSORS SPECIFICALLY DISCLAIM ANY AND ALL EXPRESS OR IMPLIED WARRANTIES, INCLUDING WITHOUT LIMITATION, ANY WARRANTIES FOR AVAILABILITY, ACCURACY, TIMELINESS, COMPLETENESS, NON-INFRINGMENT, MERCHANTABILITY OR FITNESS FOR A PARTICULAR PURPOSE. Your use of the translations is subject to all use restrictions contained in your Electronic Products License Agreement and by using the translation functionality you agree to forgo any and all claims against ProQuest or its licensors for your use of the translation functionality and any output derived there from. Hide full disclaimer
© 2018. This work is licensed under http://creativecommons.org/licenses/by/4.0/ (the “License”). Notwithstanding the ProQuest Terms and Conditions, you may use this content in accordance with the terms of the License.
Abstract
Introduction It is a well-known fact that the set ℚ ℚ of rational numbers is not complete—hence, such important constants as 2 2 or π π do not exist in ℚ ℚ . Because the way in which the set ℝ ℝ is constructed of real numbers from ℚ ℚ is quite complicated, it is usually defined axiomatically. According to the measure extension theorem, any additive and continuous mapping λ: R⟶[0, 1] can be extended from R to B , since R is an algebra and B is the σ -algebra generated by R. Axiom (S). [...]λ(A)=limn→∞λ((−∞, bn])=limn→∞an=supn∈N an. [...]we have found that any increasing sequence {an}n from the interval [0, 1]has the supremum.
You have requested "on-the-fly" machine translation of selected content from our databases. This functionality is provided solely for your convenience and is in no way intended to replace human translation. Show full disclaimer
Neither ProQuest nor its licensors make any representations or warranties with respect to the translations. The translations are automatically generated "AS IS" and "AS AVAILABLE" and are not retained in our systems. PROQUEST AND ITS LICENSORS SPECIFICALLY DISCLAIM ANY AND ALL EXPRESS OR IMPLIED WARRANTIES, INCLUDING WITHOUT LIMITATION, ANY WARRANTIES FOR AVAILABILITY, ACCURACY, TIMELINESS, COMPLETENESS, NON-INFRINGMENT, MERCHANTABILITY OR FITNESS FOR A PARTICULAR PURPOSE. Your use of the translations is subject to all use restrictions contained in your Electronic Products License Agreement and by using the translation functionality you agree to forgo any and all claims against ProQuest or its licensors for your use of the translation functionality and any output derived there from. Hide full disclaimer