1. Introduction
Over the last decades, many researchers have focused on fixed point theory since it plays a very important role in the resolution of several mathematical models in various fields, see References [1,2,3,4,5,6,7,8,9,10,11,12,13,14]. One of the tools used is the well-known Banach contraction principle, which states that if is a complete metric space and is a contraction self-mapping, then f has a unique fixed point in X. On the other hand, if f is a non-self mapping, that is, , where A and B are two subsets of X, then f might not necessary have a fixed point, which leads one to think of an approximate solution x of such that x is closet to : thereby, best proximity point theory appeared. We recall the definition of a best proximity point.
Let be a metric space, A and B two subsets of X and a mapping . We denote by the distance between A and B as follows
An element is called a best proximity point of the mapping f if
(1)
There are many variants and extensions of results for the existence of a best proximity point. For more details, we refer to References [15,16,17,18,19,20,21,22,23,24,25,26,27,28,29].
One of the generalized metric spaces is the rectangular metric space introduced first by Branciari [30]. Metric spaces endowed with a graph were introduced by Jachymski [31], which is an extension of metric spaces with partial order structures. In this paper, we consider rectangular metric spaces with the additional structure of a graph. Our contribution is that of proving the existence of a unique best proximity point for mappings satisfying different contractive conditions.
2. Preliminaries
In this section, we present some useful preliminary definitions and results related to our study. First, we remind the reader of the definition of rectangular metric spaces along with the topology.
[30] Let X be a nonempty set. If the function satisfies the following conditions for all :
-
(r1)
if and only if ;
-
(r2)
;
-
(r3)
for all different ,
[30] Let be a rectangular metric space. Then,
-
1.
a sequence in X converges to a point x if and only if .
-
2.
a sequence in X is called Cauchy if .
-
3.
is said to be complete if every Cauchy sequence in X converges to a point .
-
4.
Let be an open ball in . A mapping is continuous at if for each , there exists so that .
Now, we present the definition of a best proximity point in the rectangular metric spaces .
Let be nonempty subsets of and be a given mapping. We denote by . An element is called a best proximity point for the mapping f if . We denote by and the following sets:
(2)
(3)
The concept of P-property was defined by Raj in Reference [32].
[32] Let be a pair of non-empty subsets of such that . We say that the pair has the P-property if and only if for and .
Here, let us recall some preliminaries from graph theory. Let X be a nonempty set and . A graph G is a pair where is a set of vertices coinciding with X and the set of its edges such that . Furthermore, throughout this paper, we assume that the graph G has no parallel edges, that is, we do not allow it to get two or more edges that are incident to the same two vertices. By reversing the direction of edges in G, we get the graph denoted where its set of edges and vertices are defined as follows:
Consider the graph consisting of all vertices and edges of G and , that is,
(4)
We denote by the undirected graph obtained by ignoring the direction of edges of G.
[31] A subgraph is a graph which consists of a subset of a graph’s edges and associated vertices.
[31] Let x and y be two vertices in a graph G. A path in G from x to y of length n () is a sequence of distinct vertices such that , and for .
[31] A graph G is said to be connected if there is a path between any two vertices of G and it is weakly connected if is connected.
[31] A path is called elementary if no vertices appear more than once in it. For more details see Figure 1 and Figure 2.
Let be a rectangular metric space. The graph G may be converted to a weighted graph by assigning to each edge the distance given by the rectangular metric between its vertices. In order to later apply the rectangular inequality to the vertices of the graph, we need to consider a graph of length bigger than 2, which means that between two vertices, we can find a path through at least two other vertices.
3. Main Results
First, let be a rectangular metric space and G be a directed graph without parallel edges such that .
Let A and B be two nonempty subsets of . A mapping is said to be a G- contraction mapping if for all , with :
-
(i)
, for some ,
-
(ii)
Our first main result is as follows:
Let be a complete rectangular metric space, A and B be two nonempty closed subsets of such that has the P-property. Let be a continuous G-contractive mapping such that and . Assume that d is continuous and the following condition holds: there exist and in such that there is an elementary path in between them and .
Then, there exists a sequence with for . Moreover, if there exists a path in G between any two elements x and y, then f has a unique best proximity point.
From the condition , there exist two points and in such that and a path in G between them such that the sequence containing points of . Consequently, , and .
Given that , and from the definition of , there exists such that . Similarly, for , there exists such that .
As is a path in G then . From the above, we have and . Therefore, as f is a G-contraction, it follows that . In a similar manner, it follows that
(5)
Let . Then, is a path from to . For each , as and , then by the definition of , there exists such that . In addition, we have . As above mentioned, we obtain
(6)
Let . Then, is a path from and .
Continuing in this process, for all , we generate a path from and . As a consequence, we build a sequence where and such that
(7)
From the P-property of and (7), it follows for each ,
(8)
Next, we claim that , where C is a constant. To prove the claim, we need to consider the following two cases where is a path from to .
Note that for all , are different owing to the fact that the considered path is elementary. Then, we can apply the triangular inequality .
Case 1: (N is odd).
For any positive integer n, we get
(9)
Knowing that for all and f is a G-contraction, we obtain from (9)
(10)
By induction, it follows that for all
(11)
where .Case 2: (N is even).
By the same arguments used in Case 1, we deduce that . On the other hand, . Indeed, from (7), we have and and using the P-property, we get
(12)
Then, we conclude that where .
Let us prove that is a Cauchy sequence. Let such that . We suppose w.l.o.g that m is odd () since the case is similar. Note that , and for all n since the path is elementary. Then, using the triangular inequality of the rectangular metric, we obtain
As , then . Therefore, is a Cauchy sequence and there exists such that as .
Using the continuity of f, we get as . Now, using the continuity of the rectangular metric function, we obtain converges to as .
Since , the sequence is constant. Consequently, . Then, u is a best proximity point of f.
In order to prove the uniqueness of the best proximity point u, we assume that there exist u and such that
(13)
(14)
Knowing that the pair has the P-property, from (13) and (14), we get . Since f is a G-contraction, we obtain , which holds unless
□Let be a mapping. Define as
(15)
Let A and B be two non-empty subsets of . A mapping is said to be a G-weakly contractive mapping if for all , with :
-
(i)
, where is a continuous and nondecreasing function such that ψ is positive on , and . If A is bounded, then the infinity condition can be omitted.
-
(ii)
Our second main result is as follows:
Let be a complete rectangular metric space endowed with a directed graph, A and B be two nonempty closed subsets of such that has the P-property. Let be a continuous G-weakly contractive mapping such that . Assume that d is continuous and is a closed nonempty set. Then, there exists a sequence in such that for . Moreover, f has a unique best proximity point.
It follows from the definition of and that for every , there exists such that . Conversely, for every there exists such that . Since , for every there exists such that .
Let , then there exists such that and . On the other hand, since and , there exists such that and because f is a G-weakly contractive mapping, we get . We repeat this process in a similar way, we build a sequence in such that
(16)
(17)
Since the pair has the P-property, we conclude that for all . Then, for any positive integer n
(18)
If we denote by , from (18), is a nonnegative decreasing sequence. Hence, converges to some real number . Suppose that . As is increasing, for any positive integer n, we have
At the limit, , which is a contradiction, so , that is,
(19)
Similarly, we find that
(20)
Now, let us prove that is a Cauchy sequence.
For any , choose N such that
(21)
(22)
Let be a closed ball with center and radius . We claim that .
Using the P-property, we obtain
(23)
Consider , i.e., . We distinguish two cases and .
Case 1:.
Using the rectangular inequality, we distinguish the following two subcases:
• If , and , we have
In the case where , we obtain .
• If , and , we have
which implies that .Case 2:.
• If , and , we get
• If , and , we have
Then, , which gives that . Thus, we obtain that
(24)
Claim: If with for some , then .Let . Then,
(25)
Assume that there exists such that . From (17), we get which gives us using the P-property,
(26)
From (25) and (26), we obtain that , i.e., and the claim is proved.
From (21) and (23), we have . Then, using (24), we get , i.e.,
(27)
Since , by the precedent claim . Again, from (24), and from the claim . In this way, we obtain
(28)
Thus, the sequence is Cauchy. Since A is a closed subset of the complete rectangular metric space, there exists such that
(29)
From the continuity of f, we obtain
(30)
Then, using the continuity of the rectangular metric, we obtain
(31)
From (17), , we conclude that is a constant sequence equal to . Therefore, from (31), . Thereby, is a best proximity point of f.
Let us prove the uniqueness of the best proximity point. Consider two different best proximity points. Then, . From the P-property, we obtain . Using that f is weakly G-contractive, we get
(32)
which is a contradiction. Therefore, . □Let be a rectangular metric space and G be a directed graph. Let be two nonempty subsets of X. A non-self mapping is said to be
-
a G- proximal Kannan mapping if for , there exists such that
-
proximally G-edge preserving if for each
.
Our third main result is as follows:
Let be a rectangular metric space and G a directed graph. Let be two nonempty closed subsets of X. Assume that is nonempty and d is continuous. Let be a continuous non-self mapping satisfying the following properties:
-
T is proximal G-edge preserving and a G-proximal Kannan mapping such that .
-
There exist such that
(33)
Then, T has a best proximity point in A. Furthermore, the sequence defined by for all converges to . Moreover, if there exists a path in G between any two points of A, then the best proximity point is unique.
From (33), there exist such that
(34)
Since , we have and there exists such that
(35)
Using the proximally G-edge preserving of T, (34) and (35), we get . By continuing this process, we obtain the sequence in such that
(36)
(37)
Now, let us prove that is a Cauchy sequence in A. Note that if there exists such that , from (36), we get that is a best proximity point of T. Therefore, we may assume that for all .
Since T is a G-proximal Kannan mapping for each , we obtain , and which imply that
By induction, we obtain
(38)
As , then as . Let .
Case 1:
(39)
Case 2:
(40)
Knowing that as , we shall prove that as . From (36), we can conclude that
(41)
(42)
On the other hand, from (37) we get and . Then, since G is a connected graph, there exists a path between and in G. Therefore,
(43)
Knowing that T is a G-proximal Kannan mapping and from (41)–(43), we obtain
(44)
Therefore, from (40), we conclude that as . It follows that is a Cauchy sequence in A. Since A is closed, there exists such that as . By the continuity of T, we obtain as . Since d is assumed to be continuous, we get as . By (36), we conclude that
Thus, is a best proximity point of T and the sequence defined by converges to for all .
Let us prove the uniqueness of the best proximity point . Suppose that and are two best proximity points. Then, we obtain , and , which gives . Therefore, we get , which implies that . It is a contradiction with respect to . Then, , that is, and so the uniqueness of the best proximity point follows. □
4. Conclusions and Perspectives
In Theorems 1–3, we assumed that the rectangular metric space is continuous, which is a strong hypothesis and does not hold in general. To our knowledge, our work is the first attempt to prove best proximity point results not only in the setting of rectangular metric spaces, but with the addition of a graph theory structure. Finally, an open question, how does one prove the above three theorems when omitting the continuity of the rectangular metric?
Author Contributions
All authors read and approved the manuscript.
Funding
This research was funded by the research group Nonlinear Analysis Methods in Applied Mathematics (NAMAM) group number RG-DES-2017-01-17.
Acknowledgments
The third and fourth authors would like to thank Prince Sultan University for funding this work through the research group Nonlinear Analysis Methods in Applied Mathematics (NAMAM) group number RG-DES-2017-01-17.
Conflicts of Interest
The authors declare no conflict of interest.
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© 2019 by the authors.
Abstract
In this paper, we ensure the existence and uniqueness of a best proximity point in rectangular metric spaces endowed with a graph structure.
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1 Department of Natural Sciences, Community College Al-Riyadh, King Saud University, Riyadh 4545, Saudi Arabia; Ecole Supérieure des Sciences Economiques et Commerciales de Tunis, University of Tunis, Montfleury, Tunis 1089, Tunisia
2 Department of Mathematics, College of Education in Jubail, Imam Abdulrahman Bin Faisal University, P.O. Box 12020, Industrial Jubail 31961, Saudi Arabia;
3 Department of Mathematics and General Sciences, Prince Sultan University, Riyadh 11586, Saudi Arabia