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1. Introduction
The integral and differential operators have remarkable impact on applied sciences, and the interest of researchers is increasing day by day in this research area [1, 2]. Consider a convex function
is Hermite-Hadamard’s (see [3, 4]).
The notion of convexity is very old, and it appears in Archimedes treatment of orbit length. Nowadays, convex geometry is a mathematical subject in its own right. There are several modern works on convexity that are for the studies of real analysis, linear algebra, geometry, and functional analysis. The theory of convexity helps us to solve many applied problems. In recent years, the theory of convex analysis gains huge attention of researchers due to its interesting applications in optimizations, geometry, and engineering [5, 6].
The present paper deals with a new class of convex functions and establishes inequalities of Hermite-Hadamard and Fejér. Moreover, we develop some fractional integral inequalities. See [7, 8] for more general inequalities via convexity of functions.
The classical definition of convex functions was given in [3]. Another concept which is used widely in convex analysis is
Motivated by the above researches, [13] introduced the following class of functions.
The function
holds for
Definition 1 (see [13, 14]).
Consider
respectively, where
It is to be noted that
The Riemann integral is reduced to classical integral for
The definition of strong
2. Inequality of Hermite-Hadamard Type
In order to prove the inequality of Hermite-Hadamard type, the following lemma is very important.
Lemma 2 (see [19]).
Let
(i) If
(ii) If
Theorem 3.
Let the strongly generalized
Proof.
We begin the proof by inserting
Take
Multiplying (9) by
Now, to obtain the left-hand side of Theorem 3, we have for
Combining (12) and (13), we have
Multiplying (14) by
Together (11) and (16) give the required result.
Remark 4.
(i) Fixing
(ii) Fixing
(iii) Fixing
(iv) Applying both (ii) and (iii) on Theorem 3, we obtain classical fractional version of H-H inequality
Definition 5 (see [22]).
Let
Theorem 6 (inequality of Fejér type).
Suppose that
Proof.
Setting
Substitute
According to the given conditions of
Let
Now, take
Multiply on both sides of (26) by
Take
Similarly, we have
from definition of
Combining (29) and (30), we obtain
Combining (32) and (25) completes the theorem (17).
3. Fractional Integral Inequalities for Strongly Generalized
Lemma 7.
Consider a differentiable function
holds with
Proof.
Let
By integration by parts, we have
By combining (34), (37), and (38), we have (33). This completes the proof.
Remark 8.
Setting
Theorem 9.
Let the function
Proof.
Theorem (3) gives
Setting
Since
After combining (48) and (43), we have
Remark 10.
If one takes
Theorem 11.
Let the function
Proof.
Let
Setting
Using the inequality of power mean the definition of
This completes the proof.
Remark 12.
(i) Setting
(ii) Setting
4. Conclusion
In this paper, we established inequalities of Hermite-Hadamard and Fejér type for strongly generalized
Authors’ Contributions
All authors contributed equally in this paper.
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Abstract
In modern world, most of the optimization problems are nonconvex which are neither convex nor concave. The objective of this research is to study a class of nonconvex functions, namely, strongly nonconvex functions. We establish inequalities of Hermite-Hadamard and Fejér type for strongly nonconvex functions in generalized sense. Moreover, we establish some fractional integral inequalities for strongly nonconvex functions in generalized sense in the setting of Riemann-Liouville integral operators.
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Details

1 School of Astronautics, Beijing Institute of Technology, Beijing 100081, China
2 Department of Mathematics, University of Okara, Okara, Pakistan
3 Department of Mathematics and Statistics, University of the Lahore, Lahore, Pakistan