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Zheng Zeng 1 and Zi-tian Xie 2
Recommended by Yong Zhou
1, Department of Mathematics, Shaoguan University, Shaoguan, Guangdong 512005, China
2, Department of Mathematics, Zhaoqing University, Zhaoqing, Guangdong 526061, China
Received 6 February 2009; Revised 3 May 2009; Accepted 23 July 2009
1. Introduction
If p>1 , 1/p+1/q=1 , an ,bn >0 such that ∞>∑n=1∞anp >0 and ∞>∑n=1∞bnq >0 , then the well-known Hardy-Hilbert's inequality and its equivalent form are given by [figure omitted; refer to PDF] [figure omitted; refer to PDF] where the constant factors are all the best possible [1]. It attracted some attention in the recent years. Actually, inequalities (1.1) and (1.2) have many generalizations and variants. Equation (1.1) has been strengthened by Yang and others ( including integral inequalities ) [2-11].
In 2006, Yang gave an extension of [2] as follows.
If p>1 , 1/p+1/q=1 , r>1,1/r+1/s=1,t∈[0,1],(2-min {r,s})t+min {r,s}≥λ>(2-min {r,s})t, such that ∞>∑n=1∞np(1-t+(2t-λ)/r)-1anp >0 , ∞>∑n=1∞nq(1-t+(2t-λ)/s)-1bnq >0 , then [figure omitted; refer to PDF] B(u,v) is the Beta function.
In 2007 Xie gave a new Hilbert-type Inequality [3] as follows.
If p>1,1/p+1/q=1,a,b,c>0,2/3≥μ>0 , and the right of the following inequalities converges to some positive numbers, then
[figure omitted; refer to PDF] The main objective of this paper is to build a new Hilbert's inequality with a best constant factor and some parameters.
In the following, we always suppose that
(1) 1/p+1/q=1, p>1 , a≥0 , -1<α<1 ,
(2) both functions u(x) and v(x) are differentiable and strict increasing in (n0 -1,∞) and (m0 -1,∞), respectively,
(3) u[variant prime] (x)/uα (x),v[variant prime] (x)/vα (x) are strictly increasing in (n0 -1,∞) and (m0 -1,∞), respectively. {u[variant prime] nv[variant prime] m /[(un2 +2aunvm +vm2 )unαvmα ]} is strict decreasing on n and m ,
(4) u(n)=un ,u(n0 )=u0 ,u((n0 -1)+ )=v((m0 -1)+ )=0,u(∞)=∞,v(∞)=∞,u[variant prime] (n)=u[variant prime] n ,v(m)=vm ,v(m0 )=v0 ,v[variant prime] (m)=vm[variant prime] .
2. Some Lemmas
Lemma 2.1.
Define the weight coefficients as follows: [figure omitted; refer to PDF] [figure omitted; refer to PDF] [figure omitted; refer to PDF] [figure omitted; refer to PDF] then [figure omitted; refer to PDF] where [figure omitted; refer to PDF]
Proof.
Let f(z)=1/[(1+2az+z2 )zα ]=1/[(z-z1 )(z-z2 )zα ] then K=(2πi/(1-e-2απi ))[Res(f,z1 )+Res(f,z2 )] if a>1 then z1 =-a-a2 -1,z2 =-a+a2 -1 [figure omitted; refer to PDF] if a=cos θ (0<θ<π/2 ), then z1 =-eiθ ,z2 =-e-iθ [figure omitted; refer to PDF] On the other hand, W(p,m)<ω(p,m) . Setting u(x)=vm σ , then ω(p,m)=Kvmpα-2α-1 /(vm[variant prime])p-1 . Similarly, W...(q,n)<ω...(q,n)=Kunqα-2α-1 /(un[variant prime])q-1 .
Lemma 2.2.
For 0<[straight epsilon]<min {p,p(1-α)} one has [figure omitted; refer to PDF]
Proof.
[figure omitted; refer to PDF] The lemma is proved.
Lemma 2.3.
Setting wn =un (or vm ) and w0 =n0 (or m0 , resp.), then k>0. {τw[variant prime] /τwk } is strictly decreasing, then [figure omitted; refer to PDF] There A∈(0,τw0 [variant prime] /τw0 k ),( for any N ).
Proof.
We have [figure omitted; refer to PDF] Easily, A had up bounded when N[arrow right]∞.
3. Main Results
Theorem 3.1.
If an >0, bn >0 , 0<∑n=1∞vmpα-2α-1 /(vm[variant prime])p-1anp <∞ , 0<∑n=n0 ∞unqα-2α-1 /(un[variant prime] )q-1bnq <∞ , then [figure omitted; refer to PDF] [figure omitted; refer to PDF] K is defined by Lemma 2.1.
Proof.
By Hölder's inequality [12] and (2.5), [figure omitted; refer to PDF] setting bn =unpα-2α+p-1un[variant prime](∑m=m0 ∞am /(un2 +2aunvm +vm2 ))p-1 >0. By(3.1) we have [figure omitted; refer to PDF] By 0<∑n=n0 ∞ (unqα-2α-1 /(un[variant prime])q-1 )bnq <∞ and (3.4) taking the form of strict inequality, we have (3.1). By Hölder's inequality[12], we have [figure omitted; refer to PDF] as 0<{∑n=n0 ∞ (unqα-2α-1 /(un[variant prime])q-1 )bnq }1/q <∞ . By (3.2), (3.5) taking the form of strict inequality, we have (3.1).
Theorem 3.2.
If α=0 , then both constant factors, K and Kp of (3.1) and (3.2), are the best possible.
Proof.
We only prove that K is the best possible. If the constant factor K in (3.1) is not the best possible, then there exists a positive H (with H<K ), such that [figure omitted; refer to PDF] For 0<[straight epsilon]<min{p,q} , setting a...m =vm-[straight epsilon]/pvm[variant prime] ,b...n =un-[straight epsilon]/qun[variant prime] , then [figure omitted; refer to PDF] On the other hand (u(x)=σv(y) and v(y)=τ ), [figure omitted; refer to PDF] By (3.6), (3.7), (3.8), and Lemma 2.3, we have [figure omitted; refer to PDF] [figure omitted; refer to PDF] We have K≤H , ([straight epsilon][arrow right]0+ ) . This contracts the fact that H<K .
[1] G. H. Hardy, J. E. Littlewood, G. Pólya Inequalities , pp. xii+324, Cambridge University Press, Cambridge, UK, 1952.
[2] B. C. Yang, "On Hilbert's inequality with some parameters," Acta Mathematica Sinica. Chinese Series , vol. 49, no. 5, pp. 1121-1126, 2006.
[3] Z. Xie, "A new Hilbert-type inequality with the kernel of -3μ -homogeneous," Journal of Jilin University. Science Edition , vol. 45, no. 3, pp. 369-373, 2007.
[4] Z. Xie, B. Yang, "A new Hilbert-type integral inequality with some parameters and its reverse," Kyungpook Mathematical Journal , vol. 48, no. 1, pp. 93-100, 2008.
[5] B. Yang, "A Hilbert-type inequality with a mixed kernel and extensions," Journal of Sichuan Normal University. Natural Science , vol. 31, no. 3, pp. 281-284, 2008.
[6] Z. Xie, Z. Zeng, "A Hilbert-type integral with parameters," Journal of Xiangtan University. Natural Science , vol. 29, no. 3, pp. 24-28, 2007.
[7] W. Wenjie, H. Leping, C. Tieling, "On an improvenment of Hardy-Hilbert's type inequality with some parameters," Journal of Xiangtan University. Natural Science , vol. 30, no. 2, pp. 12-14, 2008.
[8] Z. Xie, "A new reverse Hilbert-type inequality with a best constant factor," Journal of Mathematical Analysis and Applications , vol. 343, no. 2, pp. 1154-1160, 2008.
[9] B. Yang, "On an extended Hardy-Hilbert's inequality and some reversed form," International Mathematical Forum , vol. 1, no. 37-40, pp. 1905-1912, 2006.
[10] Z. Xie, "A Hilbert-type inequality with the kernel of irrational expression," Mathematics in Practice and Theory , vol. 38, no. 16, pp. 128-133, 2008.
[11] Z. Xie, J. M. Rong, "A new Hilbert-type inequality with some parameters," Journal of South China Normal University. Natural Science Edition , vol. 120, no. 2, pp. 38-42, 2008.
[12] J. Kang Applied Inequalities , Shangdong Science and Technology Press, Jinan, China, 2004.
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Abstract
We give a new Hilbert's inequality with a best constant factor and some parameters.
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